Obtain the quadratic or the cubic polynomial as the case may be in the standard form with the following coefficients: $a=2, b=3, c=-5, d=0$.
(N/A) The standard form of a cubic polynomial is given by $P(x) = ax^3 + bx^2 + cx + d$.
Given the coefficients $a=2, b=3, c=-5$,and $d=0$.
Substituting these values into the standard form,we get:
$P(x) = 2x^3 + 3x^2 + (-5)x + 0$.
Therefore,the required polynomial is $2x^3 + 3x^2 - 5x$.
Given the coefficients $a=2, b=3, c=-5$,and $d=0$.
Substituting these values into the standard form,we get:
$P(x) = 2x^3 + 3x^2 + (-5)x + 0$.
Therefore,the required polynomial is $2x^3 + 3x^2 - 5x$.
Explore More
Similar Questions
If one zero of the quadratic polynomial $x^{2}+3x+k$ is $2$,then the value of $k$ is
Medium
View SolutionThe zero of the polynomial $p(x) = \sqrt{5}x - 5$ is . . . . . . .
Medium
View SolutionFor each of the following,find a quadratic polynomial whose sum and product of the zeroes are as given respectively. Also,find the zeroes of these polynomials by factorisation.
Sum of zeroes $= -\frac{8}{3}$,Product of zeroes $= \frac{4}{3}$
Sum of zeroes $= -\frac{8}{3}$,Product of zeroes $= \frac{4}{3}$
Medium
View SolutionIf $-2$ is a zero of the cubic polynomial $p(x) = x^3 + 6x^2 + 11x + 6$,then find the remaining zeros of $p(x)$.
Medium
View SolutionFind the zeroes of the following quadratic polynomial and verify the relationship between the zeroes and the coefficients: $x^{2}-2x-8$.
Difficult
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo